вычислить интеграл int sqrtx ln(x) dx
ln x = u du=dx/x
dv= sqrt x dx v= int sqrtx dx = 2/3 *x^3/2
ln x * 2/3 *x^3/2 — 2/3 int x^3/2* dx/x =
= ln x * 2/3 *x^3/2 — 2/3 int x^1/2* dx =
= ln x * 2/3 *x^3/2 — 4/9 x^3/2 +C