реакции в растворах электролитов - вопрос №4125239

Mg(OH)2 — основание;
CrCl3 — соль;
CdOHCl — основная соль;
Cr(OH)3 — основание;
P2O5 — оксид
CrCl3 = Cr^(3+) + 3Cl^-
CdOHCl = CdOH^+ + Cl^-
Mg(OH)2 + H2SO4 = MgSO4 + 2H2O
Mg(OH)2 + 2H^+ + SO4^(2-) = Mg^(2+) + SO4^(2-) + 2H2O
Mg(OH)2 + 2H^+ = Mg^(2+) + 2H2O
Mg(OH)2 + NaOH — нет реакции
2CrCl3 + 3H2SO4 = Cr2(SO4)3 + 6HCl
2Cr^(3+) + 6Cl^- + 6H^+ + 3SO4^(2-) = 2Cr^(3+) + 3SO4^(2-) + 6HCl
6Cl^- + 6H^+ = 6HCl
CrCl3 + 3NaOH = Cr(OH)3 + 3NaCl
Cr^(3+) + 3Cl^- + 3Na^+ + 3OH^- = Cr(OH)3 + 3Na^+ + 3Cl^-
Cr^(3+) + 3OH^- = Cr(OH)3
CdOHCl + NaOH = Cd(OH)2 + NaCl
CdOH^+ + Cl^- + Na^+ + OH^- = Cd(OH)2 + Na^+ + Cl^-
CdOH^+ + OH^- = Cd(OH)2
CdOHCl + H2SO4 = CdSO4 + H2O + HCl
CdOH^+ + Cl^- + 2H^+ + SO4^(2-) = Cd^(2+) + SO4^(2-) + H2O + HCl
CdOH^+ + Cl^- + 2H^+ = Cd^(2+) + H2O + HCl
2Cr(OH)3 +3H2SO4 = Cr2(SO4)3 + 6H2O
2Cr(OH)3 +6H^+ + 3SO4^(2-) = 2Cr^(3+) + 3SO4^(2-) + 6H2O
2Cr(OH)3 +6H^+ = 2Cr^(3+) + 6H2O
Cr(OH)3 +3NaOH = Na3[Cr(OH)6]
Cr(OH)3 + 3Na^+ + 3OH^- = 3Na^+ + [Cr(OH)6]^(3-)
Cr(OH)3 + 3OH^- = 3Na^+ + [Cr(OH)6]^(3-)
P2O5 + 3H2SO4 = 2H3PO4 + 3SO3
P2O5 + 6H^+ + 3SO4^(2-) = 6H^+ + 2PO4^(3-) + 3SO3
P2O5 + 3SO4^(2-) = 2PO4^(3-) + 3SO3
P2O5 + 6NaOH = 2Na3PO4 + 3H2O
P2O5 + 6Na^+ + 6OH^- = 6Na^+ + 2PO4^(3-) + 3H2O
P2O5 + 6OH^- = 2PO4^(3-) + 3H2O

Mg(OH)2 = MgOH^+ + OH^-      Kд1(Mg(OH)2) = ([MgOH^+]*[OH^-])/[Mg(OH)2]
MgOH^+ = Mg^(2+) + OH^-        Kд2(MgOH^-) = ([Mg^(2+)]*[OH^-])/[MgOH^+]
Cr(OH)3 = Cr(OH)2^+ + OH^-         Kд1(Cr(OH)3) = ([Cr(OH)2^+]*[OH^-])/[Cr(OH)3]
Cr(OH)2^+ = CrOH^(2+) + OH^-     Kд2(Cr(OH)2^+) = ([CrOH^(2+)]*[OH^-])/[Cr(OH)2^+]
CrOH^(2+) = Cr^(3+) + OH^-           Kд3(CrOH^(2+)) = ([Cr^(3+)]*[OH^-])/[CrOH^2+]