(x^2-5x+7)^2-(x-3)(x-2)=1
(x^2 — 5x + 7)^2 — (x — 3)(x — 2) = 1
(x^2 — 5x + 7)^2 — (x^2 — 5x + 6) = 1
(x^2 — 5x + 7)^2 — (x^2 — 5x + 7) = 0
(x^2 — 5x + 7)*(x^2 — 5x + 7 — 1) = 0
(x^2 — 5x + 7)*(x^2 — 5x + 6) = 0
x^2 — 5x + 7 = 0 x^2 — 5x + 6 = 0
D=25-28=-3<0 х1 = 2 х2 = 3
Нет корней
Ответ: 2; 3