1/x+1/x+1=x^2-2/x^2+x
(x+1)/(x^2+x) +x/(x^2+x)=(x^2-2)/(x^2+x)
x+1+x-x^2+2=0
x<>0
x+1<>0; x<>-1
-x^2+2x+3=0
x^2-2x-3=0
x1= 3
x2=-1
Ответ: х=3